246.Binary Tree Path Sum II
1.Description(Easy)
1
/ \
2 3
/ /
4 2[
[2, 4],
[1, 3, 2]
]2.Code
public ArrayList<Integer> postorderTraversal(TreeNode root) {
ArrayList<Integer> result=new ArrayList<Integer>();
if(root==null){
return result;
}
ArrayList<Integer> left=postorderTraversal(root.left);
ArrayList<Integer> right=postorderTraversal(root.right);
result.addAll(left);
result.addAll(right);
result.add(root.val);
return result;
}Last updated