129.Rehashing
1.Description(Medium)
The size of the hash table is not determinate at the very beginning. If the total size of keys is too large (e.g. size >= capacity / 10), we should double the size of the hash table and rehash every keys. Say you have a hash table looks like below:
size=3
,capacity=4
The hash function is:
here we have three numbers, 9, 14 and 21, where 21 and 9 share the same position as they all have the same hashcode 1 (21 % 4 = 9 % 4 = 1). We store them in the hash table by linked list.
rehashing this hash table, double the capacity, you will get:
size=3
,capacity=8
Given the original hash table, return the new hash table after rehashing .
Notice
For negative integer in hash table, the position can be calculated as follow:
C++/Java
: if you directly calculate -4 % 3 you will get -1. You can use function: a % b = (a % b + b) % b to make it is a non negative integer.
Python
: you can directly use -1 % 3, you will get 2 automatically.
Example
Given[null, 21->9->null, 14->null, null]
,
return[null, 9->null, null, null, null, 21->null, 14->null, null]
2.Code
此题的难度不大,只需要按照题目的要求实现代码就可以。不过需要注意的是:
C++/Java中,不能直接对负数使用取模运算,而需要用等式
a % b = (a % b + b) % b
,让所得到的hash值为非负数。所得到的新的HashTable中,可能依然存在碰撞,所以仍然需要在对应hashcode位置的ListNode tail上插入新的ListNode。
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