# 383. Ransom Note

Easy : Given two strings `ransomNote` and `magazine`, return `true` *if* `ransomNote` *can be constructed by using the letters from* `magazine` *and* `false` *otherwise*.

Each letter in `magazine` can only be used once in `ransomNote`.

 

**Example 1:**

<pre><code><strong>Input: ransomNote = "a", magazine = "b"
</strong><strong>Output: false
</strong></code></pre>

**Example 2:**

<pre><code><strong>Input: ransomNote = "aa", magazine = "ab"
</strong><strong>Output: false
</strong></code></pre>

**Example 3:**

<pre><code><strong>Input: ransomNote = "aa", magazine = "aab"
</strong><strong>Output: true
</strong></code></pre>

&#x20;

**Constraints:**

* `1 <= ransomNote.length, magazine.length <= 105`
* `ransomNote` and `magazine` consist of lowercase English letters.

**Solution:**

```cpp
class Solution {
    public boolean canConstruct(String ransomNote, String magazine) {
		if (ransomNote.length() > magazine.length()) return false;
        int[] alphabets_counter = new int[26];
        
        for (char c : magazine.toCharArray())
            alphabets_counter[c-'a']++;

        for (char c : ransomNote.toCharArray()){
            if (alphabets_counter[c-'a'] == 0) return false;
            alphabets_counter[c-'a']--;
        }
        return true;
    }
}
```


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