Amazon
  • Introduction
  • Phone Interview I
    • 53.Reverse Words in a String
    • 31.Partition Array
  • Phone Interview II
    • 167.Add Two Numbers
    • 88.Lowest Common Ancestor
  • Onsite I
    • 655.Big Integer Addition
    • 221.Add Two Numbers II
  • Onsite II
    • 158.Two Strings Are Anagrams
    • 171.Anagrams
    • 386.Longest Substring with At Most K Distinct Characters
  • Onsite III
    • 479.Second Max of Array
    • 589.Connecting Graph
  • Onsite IV
    • 532.Reverse Pairs
  • 2022
    • OA
      • work simulation
      • Greyness
      • NearestRetailer
      • Sum of Scores of Subarray
      • StrengthOfPassword
      • ProductOf1
      • Move 0/1 InArray
      • Max deviation among all substrings
      • AWS power consumption
      • searchWordResultWord
      • maxOperationOfString
      • MinHealthGame
      • EarliestMonth
      • Package ship
      • RatingConsectiveDecresing
      • LinkedListSum
      • MovingBoxes
      • ValidString
      • MaxValueAfterRemovingFromString
      • Subtree with Maximum Average
    • VO
      • 2022.3
    • BQ
      • doc
      • 2022.4
      • Freq Question
      • 11大类BQ和Follow-ups
      • Page 1
      • BQ 100
      • 35 behavioral questions asked in 95% of Amazon interviews with examples
      • Page 2
      • 反向BQ
    • LP
      • LP-1
      • LP-2
    • SD
      • Design Amazon Prime Video Recommendation System
      • Amazon Order system
    • OOD
      • Linux Find Command
      • Amazon Locker
    • AWS Identity call
    • Interviews
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  1. 2022
  2. OA

EarliestMonth

PreviousMinHealthGameNextPackage ship

Last updated 3 years ago

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a prefix sum problem - store prefix sum for each index and then check for left i and right n-i elements difference.

public static void main(String[] args){
    MinNetPrice minNetPrice = new MinNetPrice();
    System.out.println(minNetPrice.minNetPrice(new int[]{1,3,2,3}));
}
public int minNetPrice(int[] stockPrice){
    int sum = 0;
    for(int i : stockPrice){
        sum+=i;
    }
    int minNetPrice = Integer.MAX_VALUE, month=-1, n = stockPrice.length;
    int leftSum=0,rightSum = sum;
    for(int i=1;i<n;i++){
       leftSum+=stockPrice[i-1];
       rightSum-=stockPrice[i-1];
       int currNet = Math.abs((leftSum/i)-(rightSum/(n-i)));
       if(minNetPrice>currNet){
           minNetPrice = currNet;
           month = i;
           if(minNetPrice==0) break;
       }
    }
    return month;
}