479.Second Max of Array
1.Description(Easy)
Notice
2.Code
public int secondMax(int[] nums) {
int first=Math.max(nums[0], nums[1]);
int second=Math.min(nums[0], nums[1]);
for(int i=2;i<nums.length;i++){
if(nums[i]>first){
second=first;
first=nums[i];
}
else if(nums[i]>second){
second=nums[i];
}
}
return second;
}Last updated